How do you write an equation of a circle with Center (3, -2), radius = 5?

1 Answer
ali ergin
May 19, 2016

(x-3)^2+(y+2)^2=25(x−3)2+(y+2)2=25

Explanation:

C=(a,b)" coordinates of center of circle"C=(a,b) coordinates of center of circle

(x-a)^2+(y-b)^2=r^2" circle equation"(x−a)2+(y−b)2=r2 circle equation

a=3" "b=-2" "r=5a=3 b=−2 r=5

(x-3)+(y+2)=5^2(x−3)+(y+2)=52

(x-3)^2+(y+2)^2=25(x−3)2+(y+2)2=25

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