How do you write an equation of a circle with center (6,-9) and diameter = 2sqrt7?
1 Answer
Jan 29, 2016
( x - 6 )^2 + (y+9)^2 = 7(x−6)2+(y+9)2=7
Explanation:
The standard form of the equation of a circle is :
(x - a )^2 + (y - b )^2 = r^2(x−a)2+(y−b)2=r2 where ( a , b ) is the centre and r , the radius.
The data required to complete the equation is given in this
question , centre (6 , - 9 ) and r =
sqrt7 √7 hence equation is :
( x - 6 )^2 + (y + 9 )^2 = (sqrt7)^2(x−6)2+(y+9)2=(√7)2
