How do you write an equation of a line going through (1/2)^x =16^2?

1 Answer
Alan P.
Nov 23, 2016

x=-8

Explanation:

1/2=2^(-1)

rArr (1/2)^x=((2)^(-1))^x=2^(-x)

16=2^4

rArr 16^2 = (2^4)^2=2^8

Therefore
color(white)("XXX")(1/2)^x=16^2

rArr 2^(-x) = 2^8

rArr x=-8

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