How do you write an equation of a line going through $16^{5 x} = 64^{x + 7}$ $16^(5x)= 64^(x+7)$ ?

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Answer 1 · 2016-06-21T07:56:47

$x = 3$ $x=3$

$16^{5 x} = 64^{x + 7} ?$ $16^(5x)=64^(x+7) ?$

$2^{4 (5 x)} = 2^{6 (x + 7)}$ $2^(4(5x))=2^(6(x+7))$

$4 (5 x) = 6 (x + 7)$ $4(5x)=6(x+7)$

$20 x = 6 x + 42$ $20x=6x+42$

$20 x - 6 x = 42$ $20x-6x=42$

$14 x = 42$ $14x=42$

$x = 3$ $x=3$

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How do you write an equation of a line going through 165x=64x+716^(5x)= 64^(x+7)?