How do you write an equation of a line with point (2,6), slope 2?

1 Answer
Jan 18, 2017

See the entire solution process below:

Explanation:

To write this equation we can use the point-slope formula.

The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the values from the problem gives this equation:

#(y - color(red)(6)) = color(blue)(2)(x - color(red)(2))#

We can also solve for #y# to put this equation into the more familiar slope-intercept form:

The slope-intercept form of a linear equation is:

#y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

#y - color(red)(6) = (color(blue)(2) xx x) - (color(blue)(2) xx color(red)(2))#

#y - color(red)(6) = 2x - 4#

#y - color(red)(6) + 6 = 2x - 4 + 6#

#y - 0 = 2x + 2#

#y = 2x + 2#