How do you write an equation of a polynomials with zeros: -3,0, 4; degree 3?

1 Answer
Dec 6, 2017

p(x)=x^3-x^2-12xp(x)=x3x212x

Explanation:

"given the zeros of a polynomial say"given the zeros of a polynomial say

x=a,x=b" and "x=cx=a,x=b and x=c

"then the factors are "(x-a),(x-b)" and "(x-c)then the factors are (xa),(xb) and (xc)

"the polynomial is the product of the factors"the polynomial is the product of the factors

rArrp(x)=k(x-a)(x-b)(x-c)larrcolor(blue)"k is a multiplier"p(x)=k(xa)(xb)(xc)k is a multiplier

"here "x=-3,x=0,x=4larrcolor(blue)"zeros"here x=3,x=0,x=4zeros

rArr(x+3),(x-0)" and "(x-4)" are the factors"(x+3),(x0) and (x4) are the factors

"letting "k=1letting k=1

p(x)=x(x+3)(x-4)p(x)=x(x+3)(x4)

color(white)(p(x))=x(x^2-x-12)p(x)=x(x2x12)

color(white)(p(x))=x^3-x^2-12xlarrcolor(blue)"is a possible polynomial"p(x)=x3x212xis a possible polynomial