Question

How do you write an equation of the line in standard form with m=-1/2, goes through (-3/4)?

Answer 1

`x+2y-5=0`

Explanation:

When you know the slope `m` and a point `(x_0,y_0)` of a line, the equation becomes

`y-y_0=m(x-x_0)`

In your case, -assuming that with "(-3/4)" you meant the point `(-3,4)`- you have

`y-4=-1/2(x+3)`

`y=-1/2x -3/2+4`

`y=-1/2+5/2`

`2y=-x+5`

`x+2y-5=0`