How do you write as a single log for 1/3log_3x + 2/3log_3x ?
1 Answer
Oct 29, 2015
Explanation:
1/3 log_3(x) + 2/3 log_3(x) = (1/3 + 2/3) log_3(x) = log_3(x)
1/3 log_3(x) + 2/3 log_3(x) = (1/3 + 2/3) log_3(x) = log_3(x)