How do you write as a single log for $log_460 - log_44 + log_4x$ ?

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Answer 1 · 2015-12-11T19:52:19

I think you intended $log_4 60 - log_4 4 + log_4 x$ .

If so, then using the basic properties of logs this simplifies to:

$log_4 15x$

In general, $log_a b + log_a c = log_a bc$

and $log_a b - log_a c = log_a (b/c)$

So:

$log_4 60 - log_4 4 + log_4 x$

$=log_4 (60/4) + log_4 x$

$=log_4 15 + log_4 x$

$=log_4 15x$

How do you write as a single log for log_460 - log_44 + log_4x log_460 - log_44 + log_4x ?