How do you write as a single logarithm ${log}_{b} 2 + {log}_{b} x - {log}_{b} y$ $Log_b 2 + Log_bx- Log_by$ ?

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How do you write as a single logarithm ${log}_{b} 2 + {log}_{b} x - {log}_{b} y$ $Log_b 2 + Log_bx- Log_by$ ?

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Answer 1 · 2015-11-02T14:03:55

${log}_{b} 2 + {log}_{b} x - {log}_{b} y = {log}_{b} (\frac{2 x}{y})$ $log_b 2 + log_b x − log_b y = log_b ((2x)/y)$

Explanation:

${log}_{c} a + {log}_{c} b = {log}_{c} (a b)$ $log_c a + log_c b = log_c (ab)$
${log}_{c} a - {log}_{c} b = {log}_{c} (\frac{a}{b})$ $log_c a - log_c b = log_c (a/b)$

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How do you write as a single logarithm ${log}_{b} 2 + {log}_{b} x - {log}_{b} y$ $Log_b 2 + Log_bx- Log_by$ ?

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Explanation:

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How do you write as a single logarithm ${log}_{b} 2 + {log}_{b} x - {log}_{b} y$ $Log_b 2 + Log_bx- Log_by$ ?