Question

How do you write `f(x)= -2x^2+6x+2` in vertex form?

Answer 1

`- 2 ( x - 3/2 )^2 + 13/2`

Explanation:

`- 2x^2 + 6x + 2`
`= - 2 (x^2 - 3x) + 2`
`= - 2 (x^2 - 2 * 3/2 * x + (3/2)^2 - (3/2)^2) + 2`
`= - 2 (x -3/2)^2 + 2 + 9/2`
`= - 2 (x - 3/2)^2 + 13/2`