How do you write polynomial function of least degree with integral coefficients that has given zeros -5,2,1,i? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer t0hierry Jan 20, 2017 P(x) = (x+5)(x-2)(x-1)(x-i) Explanation: P(x) = (x+5)(x-2)(x-1)(x-i) is the lowest order of all polynomials with given zeroes. Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of f(x) = 5x^7 − x + 216? What are the zeros of f(x)= −4x^5 + 3? How many times does f(x)= 6x^11 - 3x^5 + 2 intersect the x-axis? What are the real zeros of f(x) = 3x^6 + 1? How do you find the roots for 4x^4-26x^3+50x^2-52x+84=0? What are the intercepts for the graphs of the equation y=(x^2-49)/(7x^4)? See all questions in Zeros Impact of this question 5221 views around the world You can reuse this answer Creative Commons License