Question

How do you write the equation for a circle with center (-2,-3) and r = 3?

Answer 1

`(x+2)^2+(y+3)^2=9`

Explanation:

The equation of a circle is:

`(x-h)^2+(y-k)^2=r^2` where h and k are the x and y values of the centre and r is the radius. We can plug in the given values to find the equation of this circle:

`(x+2)^2+(y+3)^2=3^2=9`

Answer 2

`(x+2)^2+(y+3)^2=9`

Explanation:

The standard form of the equation of a circle is.

`color(red)(|bar(ul(color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))`
where (a ,b) are the coordinates of the centre and r, the radius.

here a = -2 , b = -3 and r = 3

Substitute these values into the standard equation.

`rArr(x+2)^2+(y+3)^2=9" is the circle's equation."`