How do you write the equation in point slope form given (-3,1) and has a slope of -2?

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Answer 1 · 2016-02-26T00:37:15

#y-1=-2(x+3)#

To determine the equation of the line we can use the point slope formula and plug in the values (-3 , 1) and slope of -2 given in the question.

#(y - y_1) = m(x - x_1)#

#m = -2#
#x_1 = -3#
#y_1 = 1#

#(y - 1) = -2(x - (-3))#

The point-slope form is the following:

#y - 1 = -2(x + 3)#

Solve for #y# to get the slope-intercept form (this isn't necessary since the question asked for point-slope form).

#y - 1 = -2x - 6#

#y - 1 + 1 = -2x - 6+ 1 #

#y = -2x - 5#

Slope-intercept form is #y = mx +b#, where #m# is the slope and #b# is the y-intercept.