How do you write the equation of a line passing through the point (4,2) with the slope -3?

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Answer 1 · 2016-11-21T00:38:22

Point-slope form: #y-2=-3x+12#

First write a point-slope equation #y-y_1=m(x-x_1)#, where #(x_1,y_1)# is the given point, #(4,2)#, and #m# is the slope, #-3#.

#y-2=-3(x-4)#

#y-2=-3x+12#

For graphing, you can convert to the slope-intercept form, #y=mx+b#, by solving for #y#, where #m# is the slope and #b# is the y-intercept.

Add #2# to both sides.

#y=-3x+12+2#

#y =-3x+14#

#m=-3# and #b=14#

graph{y=-3x+14 [-10.72, 9.29, 7.66, 17.66]}