How do you write the equation of the circle where the point (-6,-5) lies on a circle whose center is at (-4,5)?

Question

How do you write the equation of the circle where the point (-6,-5) lies on a circle whose center is at (-4,5)?

1 Answer

Impact of this question

1762 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-11T19:49:40

${(x + 4)}^{2} + {(y - 5)}^{2} = 104$ $color(red)((x+4)^2+(y-5)^2=104)$

Explanation:

enter image source here
$r = \sqrt{{¯ ¯¯¯¯ ¯ A O}^{2} + {¯ ¯¯¯¯ ¯ A B}^{2}}$ $r=sqrt(bar (A O)^2+bar(A B)^2)$
$r = \sqrt{{(- 6 + 4)}^{2} + {(- 5 - 5)}^{2}}$ $r=sqrt((-6+4)^2+(-5-5)^2)$

$r = \sqrt{{(- 2)}^{2} + {(- 10)}^{2}}$ $r=sqrt((-2)^2+(-10)^2)$

$r = \sqrt{4 + 100}$ $r=sqrt(4+100)$

$r = \sqrt{104}$ $r=sqrt104$

$r^{2} = 104$ $r^2=104$

$O = (a, b) circle's center$ $O=(a,b)" circle's center"$
$O = (- 4, 5)$ $O=(-4,5)$
${(x - a)}^{2} + {(y - b)}^{2} = r^{2} circle equation$ $(x-a)^2+(y-b)^2=r^2" circle equation"$

${(x + 4)}^{2} + {(y - 5)}^{2} = 104$ $color(red)((x+4)^2+(y-5)^2=104)$

Science

Math

Humanities

... and beyond

How do you write the equation of the circle where the point (-6,-5) lies on a circle whose center is at (-4,5)?

1 Answer

Explanation:

Related questions

Impact of this question