How do you write the equation of the circle with center (-1,3) and radius 3?

1 Answer
Jim G.
Oct 8, 2016

(x+1)^2+(y-3)^2=9(x+1)2+(y−3)2=9

Explanation:

The standard form of the equation of a circle is.

color(red)(bar(ul(|color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))
where (a ,b) are the coordinates of the centre and r, the radius.

here a = -1 , b = 3 and r = 3

substitute values into the standard equation.

(x-(-1))^2+(y-3)^2=3^2

rArr(x+1)^2+(y-3)^2=9" is the equation of the circle"

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