How do you write the equation of the circle with center point (2,4) and passing through point (4,-1)?

1 Answer
Alan P.
Jun 22, 2016

(x-2)^2+(y-4)^2=29(x−2)2+(y−4)2=29

Explanation:

The radius of the circle is
color(white)("XXX")r=sqrt((2-4)^2+(-1-4)^2)=sqrt(29)XXXr=√(2−4)2+(−1−4)2=√29

The general formula for a circle with center (a,b)(a,b) and radius rr is
color(white)("XXX")(x-a)^2+(y-b)^2=r^2XXX(x−a)2+(y−b)2=r2

In this case
color(white)("XXX")(x-2)^2+(y-4)^2=29XXX(x−2)2+(y−4)2=29

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