How do you write the equation of the line, in standard form, with a slope of -5/2 passing through the point (-2,4)?

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Answer 1 · 2018-03-09T08:51:29

Standard form of the equation is #color(blue)(5x + 2y + 2 = 0#

Standard form of linear equation is #Ax + By + C = 0#

Given one point and slope of a line, we can write the equation of the line using formula

#(y - y_1) = m (x_1 - x_1)#

Given : (x_1 = -2, y_1 = 4, m = -5/2#

The equation is #y - 4 = (-5/2) * (x + 2)#

#2y - 8 = -5x - 10#

#2y + 5x -8 + 10 = 0#

#color(blue)(5x + 2y + 2 = 0#