Question

How do you write the equation of the line through (-2, -1) that is parallel to the line 5x + 3y =9?

Answer 1

`y=(-13-5x)/3`

Explanation:

Get y by itself for an easier graph equation, `3y=9-5x`, `y=(9-5x)/3`. Plugging in `-2` gets you `6 1/3`. In order to get a parallel equation to run through `(-2,-1)`, you need to shift the y down by `7 1/3`. So `y=(9-5x)/3-7 1/3`. Which can be simplified to `y=(-13-5x)/3`.