How do you write the equation #y= -3 (x-3) (x+2)# in standard form?

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Answer 1 · 2016-11-10T19:59:54

Please see the explanation for steps leading to the standard form:

#y = -3x^2 + 3x + 18#

Use the F.O.I.L method to multiply the binomials:

#y = -3(x^2 + 2x - 3x - 6)#

Combine the x terms into one:

#y = -3(x^2 - x - 6)#

Use the distributive property:

#y = -3x^2 + 3x + 18#