Question

How do you write the point slope form of an equation for a lint that passes through (1,-4) with m=-8/3?

Answer 1

`y+4=-8/3(x-1)`

Explanation:

The equation of a line in `color(blue)"point-slope form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))`
where m represents the slope and `(x_1,y_1)" a point on the line"`

`"here " m=-8/3" and " (x_1,y_1)=(1,-4)`

Substitute these values into the equation.

`y-(-4)=-8/3(x-1)`

`rArry+4=-8/3(x-1)larrcolor(red)" in point-slope form"`