How do you write the point slope form of an equation for a lint that passes through (9,1) with m=2/3?

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Answer 1 · 2017-02-22T13:56:54

#(y - color(red)(1)) = color(blue)(2/3)(x - color(red)(9))#

The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the slope and point from the problem gives:

#(y - color(red)(1)) = color(blue)(2/3)(x - color(red)(9))#