Question

How do you write the point slope form of the equation given (4,-5) and (0,-1)?

Answer 1

The equation of the line is `y = -x-1`

Explanation:

The slope = `(y_2-y_1)/(x_2-x_1)= (-1-(-5))/(0-4)=-4/4=-1`
Let the equation of the line is `y=mx+c or y= -1*x+c` The point `(4,-5)` is on the line , so it will satisfy the equation. `y= -x=c or -5= -4+c :. c =-5+4=-1` Hence the equation of the line is `y = -x-1` graph{-x-1 [-10, 10, -5, 5]} [Ans]