How do you write the polynomial function with the least degree and zeroes -2, -1, 1? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer George C. Oct 25, 2015 f(x) = x^3+2x^2-x-2f(x)=x3+2x2−x−2 Explanation: f(x) = (x+2)(x+1)(x-1) = (x+2)(x^2-1) = x^3+2x^2-x-2f(x)=(x+2)(x+1)(x−1)=(x+2)(x2−1)=x3+2x2−x−2 Any polynomial in xx with these zeros will be a multiple - scalar or polynomial - of this f(x)f(x). Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of f(x) = 5x^7 − x + 216f(x)=5x7−x+216? What are the zeros of f(x)= −4x^5 + 3f(x)=−4x5+3? How many times does f(x)= 6x^11 - 3x^5 + 2f(x)=6x11−3x5+2 intersect the x-axis? What are the real zeros of f(x) = 3x^6 + 1f(x)=3x6+1? How do you find the roots for 4x^4-26x^3+50x^2-52x+84=04x4−26x3+50x2−52x+84=0? What are the intercepts for the graphs of the equation y=(x^2-49)/(7x^4)y=x2−497x4? See all questions in Zeros Impact of this question 1322 views around the world You can reuse this answer Creative Commons License