How do you write the standard form equation of the parabola #y = 1/2(x - 4)² + 13#?
1 Answer
Jun 20, 2018
Explanation:
#"the equation of a parabola in "color(blue)"standard form"# is.
#•color(white)(x)y=ax^2+bx+c color(white)(x);a!=0#
#"expand "(x-4)^2" and arrange into form"#
#y=1/2(x^2-8x+16)+13#
#color(white)(y)=1/2x^2-4x+8+13#
#color(white)(x)=1/2x^2-4x+21larrcolor(blue)"in standard form"#
