Question

How do you write the standard form of a line given (–1, 4) with a slope of –1?

Answer 1

`x+y-3=0`

Explanation:

Standard form for the equation of a line is

`ax + by + c = 0`

We begin by using the point slope form of the line

`(y-y_1) = m(x-x_1)`

`y - 4 = -1(x-(-1))`

`y-4 = -x-1`

`x+ y-4 = cancel(-x) cancel(+x)-1`

`x+ y-4 + 1= cancel(-1) cancel(+1)`

`x+y-3=0`