How do you write the standard form of the equation of the line with slope 3/5 passing through the point (-2,-8)?

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Answer 1 · 2016-07-21T10:06:29

#y = 3/5x +6 4/5#

There is a nifty formula for finding the equation of a straight line if we know the slope, #m# and one point #(x_1, y_1)#

#y-y_1 = m(x-x_1)#
Substitute #m = 3/5 and (-2,-8)#

#y -(-8) = 3/5(x-(-2)#)

#y+8 = 3/5x +6/5#

#y = 3/5x + 1 1/5 -8#

#y = 3/5x +6 4/5#