How do you write the trigonometric form of #4#?

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Answer 1 · 2017-01-15T00:16:50

The trigonometric form of a complex number is

#z=x+y*i=r*(costheta+isintheta)#

where

#r=sqrt(x^2+y^2)#

and

#theta=tan^-1(y/x)#

For #4# we have that

#z=4=4+0*i# hence #x=4# ,#y=0#

therefore #r=4# and #theta=0#

Hence in trigonometric form

#z=4*(cos0+isin0)#