Question

How do you write the Vertex form equation of the parabola `y = x^2 -12`?

Answer 1

In strict vertex form the equation is:

`y = 1(x-0)^2+(-12)`

Explanation:

Vertex form is:

`y = a(x-h)^2 + k`

where `(h, k)` is the vertex and `a` the multiplier.

In our case `(h, k) = (0, -12)`, `a=1` and we can write:

`y = 1(x-0)^2+(-12)`