Question

How do you write the vertex form equation of the parabola `y=x^2-2x-5`?

Answer 1

`y = (x - 1)^2 - 6`

Explanation:

`y = x^2 - 2 x -5`
`y = (x -1)^2 -(-1)^2 -5`
`y = (x - 1)^2 - 6`

since a coeficient of `(x-1)^2` is positive value, it has minimum at `-6` and it axis of simetry at `x = 1`.