Question

How do you write the vertex form equation of the parabola `y=x^2+5x-6`?

Answer 1

`Vertex (-5/2, -49/4)`

Explanation:

x-coordinate of vertex:
`x = -b/(2a) = -5/2`
y-coordinate of vertex:
`y(-5/2) = 25/4 - 5(5/2) - 6 = -25/4 - 24/4 = - 49/4`
Vertex `(-5/2, -49/4)`
Vertex form of y:
`y = (x + 5/2)^2 - 49/4`