How do you write the vertex form equation of the parabola #y=(x-4)(x-8)#?

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Answer 1 · 2018-07-07T11:24:43

Vertex form of equation is # y= (x-6)^2-4#

#y=(x-4)(x-8) or y= x^2-12 x +32# or

# y= (x^2-12 x +36)-36+32# or

# y= (x-6)^2-4# Comparing with vertex form of

equation #f(x) = a(x-h)^2+k ; (h,k)# being vertex we find

here #h=6 , k= -4 #, so vertex is at #(6,-4)# and vertex form of

equation is # y= (x-6)^2-4#

graph{(x-4)(x-8) [-10, 10, -5, 5]} [Ans]