How do you write #y=x^2+16x+14# in vertex form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Justin May 27, 2017 #y = (x+8)^2 -50# Explanation: By completing the square: #y = x^2 + 16x + (16/2)^2 - (16/2)^2 + 14# #y = (x+8)^2 - 64 + 14# #y = (x+8)^2 -50# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 3709 views around the world You can reuse this answer Creative Commons License