How do you write y=x^2+7x-1y=x2+7x−1 in vertex form?

1 Answer
Nghi N.
Jul 30, 2016

y = (x + 7/2)^2 - 53/4y=(x+72)2−534

Explanation:

x-coordinate of vertex:
x = -b/(2a) = -7/2x=−b2a=−72
y-coordinate of vertex (when x = -7/2x=−72):
y(-7/2) = 49/4 - 7(7/2) - 1 = 49/4 - 49/2 - 1 = -53/4y(−72)=494−7(72)−1=494−492−1=−534
Vertex (-7/2, -53/4)(−72,−534)
Vertex form of y:
y = a(x + b/(2a)) + y(-b/(2a)) y=a(x+b2a)+y(−b2a)
y = (x + 7/2)^2 - 53/4y=(x+72)2−534

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