How do you write #y = x^2 - 9x - 10# into vertex form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer crayon Apr 18, 2018 #(y+121/4)=(x-9/2)^2# Explanation: #" "y=x^2-9x-10# #" "y=x^2-2*9/2x+81/4-121/4# #" "y+121/4=x^2-2*9/2x+81/4# #" "(y+121/4)=(x-9/2)^2# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 2800 views around the world You can reuse this answer Creative Commons License