Question

How does a buffer affect pH?

Answer 1

`pH=pK_a+log_10{[[A^-]]/[[HA]]}`

Explanation:

So when `[A^-]=[HA]`, `pH=pK_a` because `log_10{[[A^-]]/[[HA]]}=log_10(1)=0`

[See this old answer.](https://socratic.org/questions/how-do-buffers-maintain-ph)