How does concentration affect SN2 reactions?

1 Answer

Increasing the concentration of either the nucleophile or the substrate increases the reaction rate.

In an #"S"_"N"2# reaction, one bond is broken and another bond is formed at the same time.

Consider the reaction of hydroxide ion with chloromethane.

![Chemical reaction with bond from http://iverson.cm.utexas.edu](http://iverson.cm.utexas.edu/courses/310N/ReactMoviesFl05%20/SN2%20scheme.gif)

Both reactants are involved in the transition state, so this is a bimolecular reaction.

The rate law expression is:

r = k[CH₃Br][OH⁻]

This says that the reaction rate is directly proportional to [OH]⁻ and [CH₃Br].

If you increase the concentration of any reactant, the reaction rate will increase.

Increasing the concentration of OH⁻ will increase the rate, because there are more OH⁻ ions attacking the substrate.

Increasing the concentration of CH₃Br will increase the rate, because there are more CH₃Br molecules available to be attacked.

Here's a video on #"S"_"N"2# reactions.