Question

How high can a baseball player throw a ball in the air if he can throw it with initial velocity 160 km/h? What would that be standard units?

Answer 1

`100.68m`, rounded to two decimal places

Explanation:

Initial velocity `u=160kmh^-1`
Converting in SI units we get `u=160xx1000/3600=44.bar4ms^-1`

When the ball is thrown up, assuming vertically, gravity `g=9.81ms^-2` will slow it down as it is acting against the direction of motion. At the highest point `h` the final velocity `v` will be equal to `0`. Ignoring air friction.
Applicable kinematic equation is
`v^2-u^2=2gh`
Inserting given values we get
`0^2-(44.bar4)^2=2xx(-9.81)xxh`
`=>h=100.68m`, rounded to two decimal places