How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH

1 Answer
Jul 1, 2014

This is a typical stoichiometry question.To answer this question you want to get a relationship between Na2O and NaOH.

So you can get a relationship between the moles of Na2O
and moles of NaOH by the concept of stoichiometry.

Na2O + H2O ----------------> 2 NaOH.

According to above balanced equation we can have the stoichiometry relationship between Na2O and NaOH. as 1:2

It means 1 moles of Na2O is required to react with one mol of H2O to produce 2 moles of NaOH.

in terms of mass 1 mole of Na2O has mass 62 g on reaction with water produces 2 moles of NaOH or 80 g of NaOH.

62 g of Na2O produces 80 g of NaOH.

1g of NaOH is produced from 62/80 g of Na2O

1.6 x 102 g of NaOH will require 62 x 1.6 x 102 g / 80 of Na2O

124g of Na2O.