How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---> 2 NaOH

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Answer 1 · 2014-07-01T16:53:34

This is a typical stoichiometry question.To answer this question you want to get a relationship between $N a_{2}$ $Na_2$ O and NaOH.

So you can get a relationship between the moles of $N a_{2}$ $Na_2$ O
and moles of NaOH by the concept of stoichiometry.

$N a_{2}$ $Na_2$ O + $H_{2}$ $H_2$ O ----------------> 2 NaOH.

According to above balanced equation we can have the stoichiometry relationship between $N a_{2}$ $Na_2$ O and NaOH. as 1:2

It means 1 moles of $N a_{2}$ $Na_2$ O is required to react with one mol of $H_{2}$ $H_2$ O to produce 2 moles of NaOH.

in terms of mass 1 mole of $N a_{2}$ $Na_2$ O has mass 62 g on reaction with water produces 2 moles of NaOH or 80 g of NaOH.

62 g of $N a_{2}$ $Na_2$ O produces 80 g of NaOH.

1g of NaOH is produced from 62/80 g of $N a_{2}$ $Na_2$ O

1.6 x $10^{2}$ $10^2$ g of NaOH will require 62 x 1.6 x $10^{2}$ $10^2$ g / 80 of $N a_{2}$ $Na_2$ O

124g of $N a_{2}$ $Na_2$ O.