How many grams of NaOH is produced from 1.20 x 10^21.20x102 grams of Na_2ONa2O? Na_2O + H_2O -> 2NaOHNa2O+H2O2NaOH

1 Answer
Jul 20, 2014

If we begin the problem with 120. grams of Na_2ONa2O and we are trying to find the mass of NaOHNaOH that can be produced, this is a gams to grams stoichiometry problem.

grams -> mols -> mols -> gramsgramsmolsmolsgrams

120. g Na_2O120.gNa2O x (1 mol Na_2O) / (62. g Na_2O)1molNa2O62.gNa2O x (2 mol NaOH) / (1 mol Na_2O)2molNaOH1molNa2O x (40. g NaOH) / (1 mol NaOH)40.gNaOH1molNaOH =

the gfm of Na_2ONa2O is (2 x 23 + 1 x 16 = 62)
the gfm of NaOHNaOH is (1 x 23 + 1 x 16 + 1 x 1 = 40)

The mole ratio from the balanced chemical equation is 2 moles of NaOHNaOH for every mole mole of Na_2ONa2O.

The final calculation is
120 x 2 x 40 / 62 = 154.8387

The final solution comes to 154. grams NaOH154.gramsNaOH


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