How much energy is in a wave that has a wavelength of 1.3 pm?

1 Answer
Oct 19, 2016

epsilon=hnuε=hν, where h="Planck's constant"=6.626xx10^(-34)J*sh=Planck's constant=6.626×1034Js

Explanation:

Here nu=c/lambdaν=cλ and thus epsilon=nuxx6.626xx10^(-34)J*sε=ν×6.626×1034Js

=(3.00xx10^8*ms^-1xx6.626xx10^(-34)J*s)/(1.3xx10^-12m)=3.00×108ms1×6.626×1034Js1.3×1012m.

This calculation gives an answer in "Joules"Joules as required.