How much power is produced if a voltage of $2 V$ $2 V$ is applied to a circuit with a resistance of $16 Omega$ ?

Question

1540 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-22T09:59:48

$"0.25 W"$

We know that

$"electric power"$ $= "voltage" xx "current"$

Given:

According to Ohm's Law,

$V=IR$

$:. I = V/R$

So

$I = "2 V"/(16 \ Omega) =1/8 \ "A"$

Therefore,

$P=VI$

$P = "2 V" * 1/8 \"A"$

$P = 1/4 \ "W" = "0.25 W"$

How much power is produced if a voltage of 2 V2V2 V is applied to a circuit with a resistance of 16 Omega16 Omega?