Question

How much power is produced if a voltage of `5 V` is applied to a circuit with a resistance of `96 Omega`?

Answer 1

The power is approximately `0.26` Watts

Explanation:

Let `I=` current, `P=` power, `V=` voltage, and `R=` resistance.

Ohm's law states

`V=IR`

We can solve this for current.

`I=V/R`

We also know that

`P=IV`.

We can eliminate the current with Ohm's Law.

`P=V^2/R=5^2/96~~0.26` Watts

Answer 2

Around `0.26` watts

Explanation:

Ohm's law states that,

`V=IR`

• `I` is the current in amperes

• `R` is the resistance in ohms

`<=>I=V/R`

Meanwhile, power is measured through,

`P=IV`

• `V` is the voltage in volts

`<=>I=P/V`

Through the two equations, we get a relationship:

`V/R=P/V`

`P=V^2/R`

Now, we can simply plug in the values, and get:

`P=(5 \ "V")^2/(96 \ Omega)`

`=(25 \ "V"^2)/(96 \ Omega)`

`~~0.26 \ "W"`