How much power is produced if a voltage of $6 V$ is applied to a circuit with a resistance of $42 Omega$ ?

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Answer 1 · 2018-06-22T14:19:41

Find the current by $I=E/R =6/42=0.1428" amperes."$

$"Power= voltage "xx" current " 6 xx 0.1428= 0.88571" watts."$

Answer 2 · 2018-06-23T04:23:06

Approximately $0.86$ watts.

Power is related through voltage and resistance by the equation:

$P=V^2/R$

where:

$P$ is the power in watts

$V$ is the voltage in volts

$R$ is the resistance in ohms

So, we get:

$P=(6 \ "V")^2/(42 \ Omega)$

$=(36 \ "V"^2)/(42 \ Omega)$

$~~0.86 \ "W"$

How much power is produced if a voltage of 6 V6 V is applied to a circuit with a resistance of 42 Omega42 Omega?