How much power is produced if a voltage of $6 V$ $6 V$ is applied to a circuit with a resistance of $16 Omega$ ?

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Answer 1 · 2018-03-11T12:32:22

Power dissipated $P$ across a resistor of resistance $R$ due to application of voltage $V$ is $V^2/R$

Given, $V=6,R=16$

So, $P=6^2/16=2.25$ watt

Answer 2 · 2018-03-11T12:32:39

$P=2.25\ \text{W}$

![ hyperphysics.phy-astr.gsu.edu )

By putting the given values in $\ \ P=V^2/R\ \$ , we have:

$P=\frac{6^2}{16}$

$P=2.25\ \text{W}$

That's it!

How much power is produced if a voltage of 6 V6V6 V is applied to a circuit with a resistance of 16 Omega16 Omega?