How much power is produced if a voltage of $6 V$ is applied to a circuit with a resistance of $60 Omega$ ?

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Answer 1 · 2016-02-22T12:20:21

Power $=600mW$

Things you need to know:

$P=IV$ (Power equals current times voltage)

$I=V/R$ (Current equals voltage divided by resistance

$1" Ampere" = (1 " Volt")/(1 "Ohm")$

$1 " Watt" = 1 " Ampere" * 1" Volt"$

$1 " miliWatt (mW)" = 1" Watt"$

Application

$I= (6" V")/(60 Omega) = 0.1 " A"$

$P= 0.1" A"xx6" V"= 0.6 " W" = 600" mW"$

How much power is produced if a voltage of 6 V6 V is applied to a circuit with a resistance of 60 Omega60 Omega?