How much power is produced if a voltage of 7 V is applied to a circuit with a resistance of 42 Omega?

2 Answers
Jun 29, 2018

The power is =1.17W

Explanation:

The power is

P=UI

and Ohm's Law is

U=RI

I=U/R

Therefore,

P=U*U/R=U^2/r

The voltage is U=7V

The resistance is R=42 Omega

Therefore,

The power is

P=(7^2)/42=49/42=1.17W

Jun 29, 2018

Approximately 1.17 watts.

Explanation:

Power in here is given by the equation:

P=V^2/R

where:

  • P is the power in watts

  • V is the voltage in volts

  • R is the resistance in ohms

So, we get:

R=(7 \ "V")^2/(42 \ Omega)

=(49 \ "V"^2)/(42 \ Omega)

~~1.17 \ "W"