How much stronger is the gravitational pull of Saturn from the sun?

Question

5546 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-29T09:48:14

$F_(Gravity) = 33.6653 * 10^23 (Nm^2)/(kg^2)$

We know:

$F_(Gravity) = G (Mm)/R^2$

Now, we have the value of $G$ . Consider $M$ as mass of Sun. $R$ the distance between Saturn and Sun and $m$ mass of Saturn

So:

$G = 6.673 * 10^-11 (Nm^2)/(kg^2)$
$M = 1.989 * 10^30 kg$
$m = 5.683 * 10^26 kg$
$R = 1.433 * 10^11 m$

$F_(Gravity) = 6.673 * 10^-11 [(1.989 * 10^30 kg ) * (5.683 * 10^26 kg)]/ (1.433 * 10^11)^2$

$= 6.673 * 10^-11 (11.3035 * 10^56) / (2.0535 * 10^22)$

$= 6.673 * (11.3035 * 10^23) / 2.0535$

$= 6.673 * 5.045 * 10^23$

$F_(Gravity) = 33.6653 * 10^23 (Nm^2)/(kg^2)$

This is the force of gravity between Saturn and Sun.