How to evaluate 8P7?
1 Answer
Aug 11, 2017
Explanation:
#"using the definition of "^nP_r=(n!)/((n-r)!)#
#"where "n! =n(n-1)(n-2)...... xx1#
#rArr^8P_7=(8!)/(1!)#
#color(white)(xxxxx)=(8xx7xx6xx5xx4xx3xx2)/1#
#color(white)(xxxxx)=40320#